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12r^2+139r-60=0
a = 12; b = 139; c = -60;
Δ = b2-4ac
Δ = 1392-4·12·(-60)
Δ = 22201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{22201}=149$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(139)-149}{2*12}=\frac{-288}{24} =-12 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(139)+149}{2*12}=\frac{10}{24} =5/12 $
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